In a hydrogen atom the electron and proton spins can combine in four ways: the SINGLET state has an energy J below the three TRIPLET states , and which are degenerate in zero magnetic field. The energies of the singlet and triplet states are not shifted much by a weak magnetic field (where is the magnitude of the [negative] magnetic moment of the triplet state), but the states split by 1,±1 = ±mB.
The so-called BREIT-RABI DIAGRAM shown above illustrates this magnetic field dependence of the energy levels. [In reality the Jz = 0 states curve up and down in strong fields and the singlet-triplet energy difference is much larger than shown in this illustration; but this picture is qualitatively correct in the limit of low magnetic fields.]
ANSWER: This is a simple Boltzmann distribution: probability of singlet state where is the partition function. For B=0, , giving . At J, and , giving or = fraction of atoms in the singlet state.
ANSWER: or .
ANSWER: As , and the exponentials all approach unity; the two in the numerator cancel, giving . As , and . However, since , even faster, so . Of course, in between must have nonzero values and there must be a peak in the magnitude somewhere. This could be found by differentiating with respect to and setting the derivative equal to zero, but this was not requested. An example is shown below for the case of .
ANSWER: This is easy if we apply the principles of diffusive equilibrium to a given single-particle state of energy : it may be populated by either one particle (N=1) or none (N=0); all other values of N are explicitly forbidden by the Pauli principle. We use , where is the Gibbs sum. In this case, . Since this gives .
ANSWER: The graph below shows f as a function of (i.e. in units of ) for and for . For z=1 ( or x=0) we always get and for (same as or ) we always get . For (same as or ) we get if and if . That case () also gives f = 0.119 at (z=2), as shown. The main thing to realize here is that becomes more and more like a step function as gets larger and larger (i.e. at low temperature).
ANSWER: At the distribution becomes a simple step function at : all states below the Fermi energy are filled (N=1) and all states above are empty (N=0).
ANSWER: Of the many ways to approach this part, the easiest is to just think about it! Since the chemical potential is the incremental change in free energy as the last particle is added (), and the free energy at , is just the energy level at which the last particle goes in. For spin-1/2 particles, two can go into each state ( and ) and the states are evenly spaced, , so the last particle goes in at and that is the chemical potential at or FERMI ENERGY: .
Note: it has been brought to my attention that some people had seen a derivation of the Fermi-Dirac distribution function before, while others had not; this was correlated with which Engineering specialization people had been following. Since this question is easy to answer if you grasp the basic approach and almost impossible to solve by plugging in standard formulas, it was an excellent test of your ability to synthesize ideas (the whole point of a Physics education) but an unfair one because of the importance of ``prior knowledge.'' I will try to take this into account when making up final marks, by noting which programs people are in and which courses you have taken previously. I may need to get that information from you on the Web.